3x^2+40x=128

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Solution for 3x^2+40x=128 equation:


Simplifying
3x2 + 40x = 128

Reorder the terms:
40x + 3x2 = 128

Solving
40x + 3x2 = 128

Solving for variable 'x'.

Reorder the terms:
-128 + 40x + 3x2 = 128 + -128

Combine like terms: 128 + -128 = 0
-128 + 40x + 3x2 = 0

Factor a trinomial.
(-16 + -1x)(8 + -3x) = 0

Subproblem 1

Set the factor '(-16 + -1x)' equal to zero and attempt to solve: Simplifying -16 + -1x = 0 Solving -16 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '16' to each side of the equation. -16 + 16 + -1x = 0 + 16 Combine like terms: -16 + 16 = 0 0 + -1x = 0 + 16 -1x = 0 + 16 Combine like terms: 0 + 16 = 16 -1x = 16 Divide each side by '-1'. x = -16 Simplifying x = -16

Subproblem 2

Set the factor '(8 + -3x)' equal to zero and attempt to solve: Simplifying 8 + -3x = 0 Solving 8 + -3x = 0 Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -3x = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -3x = 0 + -8 -3x = 0 + -8 Combine like terms: 0 + -8 = -8 -3x = -8 Divide each side by '-3'. x = 2.666666667 Simplifying x = 2.666666667

Solution

x = {-16, 2.666666667}

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